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Shell Script: Return Last Directory In A Path

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  #1  
Old 01-05-2007, 11:33 PM
mrbt mrbt is offline
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Posts: 87

Shell Script: Return Last Directory In A Path


I have a list of paths, e.g.

/home/user/site/examplel.com/html/journal/
/home3/oser/site/example.org/html/

What I'd like to do is just pull out and off that last directory, leaving behind


/home/user/site/examplel.com/html/
/home3/oser/site/example.org/



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  #2  
Old 01-06-2007, 02:38 PM
mrbt mrbt is offline
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Posts: 87
I just relized this should not be in Tutorials, can someone delete it, I'll post in the discussions forum, sorry, I'm a moron

  #3  
Old 01-27-2007, 03:36 PM
hkrental hkrental is offline
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Join Date: Sep 2006
Location: Hong Kong
Posts: 17
What I will do:

1) use split to separate "/" character, put them in a list. [using split]
2) counter the no. of element in the list, say n
3) loop n-1 times to concentrate the list into the directory again [in a for loop]

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  #4  
Old 06-24-2008, 04:37 AM
focusinterview focusinterview is offline
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And I thought you posted a tutorial on SSH

  #5  
Old 06-06-2009, 01:52 AM
txspaderz txspaderz is offline
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Join Date: May 2008
Location: Houston
Posts: 43
*

I know this thread is old, but it might help someone else who might be looking for info.

One way of doing is below:

Put your list of paths in a file (in this case test):

Code:
root@server[~]# cat test | cut -d "/" -f1,2,3,4,5
/home/user/site/examplel.com
/home3/oser/site/example.org
root@server[~]#

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