Web Hosting Talk : Web Hosting Main Forums : Programming Discussion : Wrong datatype for second argument for in_array()

[codetr]

Hello,

I wrote a little function;

PHP Code:

<?php session_start(); ob_start();
$salladim = $_SESSION['salla'];
$salladin =  isset($_GET['url'])?$_GET['url']:'' ;
 
if(!in_array($salladin,$salladim))
{
    header( 'refresh: 1; url='.$_SERVER['HTTP_REFERER'].'' );
echo '<h2>Hazirlaniyor...</h2>';
    exit();
}

When i run this code, i get the following error :

PHP Code:

PHP Warning:  in_array() [<a href='function.in-array'>function.in-array</a>]: Wrong datatype for second argument in /home/site/public_html/do.php on line 5 


[kjsrs]

What do you get if you do:

PHP Code:

var_dump($_SESSION['salla']); 


It looks like your session variable is not an array, which it needs to be for the second argument in in_array().

[codetr]

PHP Code:

var_dump($_SESSION['salla']); 


not working

[codetr]

how to fix this error

[quantumphysics]

do you even have a "salla" in your session?

[codetr]

Originally Posted by quantumphysics

do you even have a "salla" in your session?

this script

PHP Code:

<?php session_start();
function kodsalla($uzunluk) 
{
$karakterler = "0123456789"."ABCDEFGHIJKLMNOPQRSTUVWXYZ";
$kod = "";
  while(strlen($kod) < $uzunluk) 
  {
    $kod .= substr($karakterler, (rand() % strlen($karakterler)), 1);
  }
  return($kod);
}
$kodsalla = kodsalla(8);

$_SESSION['salla'][] = $kodsalla;

[codetr]

how to fix this error pls help me thanks

PHP Code:

var_dump($_SESSION['salla']); 


PHP Code:

array(1) {
  [0]=>
  string(8) "4AZWX25C"
} 


[sea otter]

Your code actually runs fine for me and does not generate any errors.

All I can think is...try putting session_start() after ob_start().

PHP output buffering and session handling is sometimes configured in such a way that it requires ob_start() to come before session_start(). In other cases, the order doesn't matter.