Dunno if I'm doing something wrong or what...

here's the code:


// Doesn't work
if ($array1['val'] == $array2['val']) {
echo "Correct";
} else {
echo "Wrong";
}

// Does work
$var1 = $array1['val'];
$var2 = $array2['val'];

if ($var1 == $var2) {
echo "Correct";
}


As you can see they both have the same values, but for some reason when I try to do it as an assoc. array it returns false... any ideas? Isn't that veird?

I assume val could be one of two things. Either a Variable or a set term. If its meant to be a variable it needs a $ infront ot it. If it not meant to be a variable then I can't answer your question as my php knownledge is limited due to the fact I am still learning it myself.

Try doing a


printf("Check: %s == %s?\n",$arr1['val'],$arr2['val']);


before the comparison.

eval("\$ticket[status] = \"$settings[default_closed]\";");

Those are the "real" array names... and it evals true. I must have a screw up somewhere else :confused:

n/m found the problem :p... I somehow had it in a loop so $ticket['status'] kept on getting closed appended to it so it was actually

ClosedClosedClosed == Closed :p.

Use the in_array function (http://www.php.net/in_array) function for the above query.

Nope... in_array() only works if you wan't to fine the value ANYWHERE in the array. In my case I only wan't the two above keys to equal.

Furthermore, in_array() requires that the needle be a string, not an array, so even if I wanted to find it anywhere in the array it'd require more code:


if (in_array("val", $array) && in_array("val", $array2)) {

// Much better for my purpose:
if ($array['key'] == $array2['key']) {