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View Full Version : Need a lawyer to solve this...


imago-allan
08-11-2002, 02:44 AM
Hi!

Guess everyone is serious nowadays...

Here is a puzzle:

An old man died and he left in his last will and testament to wit:

"I will divide my 11 cars to my 3 sons. The oldest will get 1/2 of it.
The middle will get 1/4 and the youngest will get 1/6. It has to be divided such that no complaint shall be coming from each one."

Now, if you are the lawyer, how will you go about dividing the cars?

:)

Incognito
08-11-2002, 09:55 AM
6, 3, 2

All get their percent rounded up, so even though the three parts didn't totaly 100%, the three will get all the cars and all will get more (in partial cars) that technically required.

FHDave
08-11-2002, 10:13 AM
Actually you need not to round up.
You can see the problem in different way. The middle and youngest should get 1/2 and 1/3 as many cars as the oldest respectively.

Hence, 6, 3, 2 does solve the problem.

epgs
08-11-2002, 10:24 AM
Actually you sell all the cars and divide the money using the percentages requested

adammc
08-11-2002, 10:43 AM
Actually you sell all the cars and divide the money using the percentages requested

the will says they get the cars...so I don't think you can sell them...but then again, I'm no expert so....

DoobyWho
08-11-2002, 10:55 AM
6, 3, 2 ;-)

imago-allan
08-11-2002, 11:00 AM
Hehehe. :) But 6 is not 1/2 of eleven! 1/2 of 11 is only 5 1/2. If I am the middle child I will complain. :) It is not fair.

Haha!

What will you do if you are the lawyer?

The answer is 6, 3, 2. But, the lawyer has to do something first.

:)

EDIT: The number of cars should match the fraction of the total cars.

DoobyWho
08-11-2002, 11:01 AM
uhh.. hit the middle son? lol , i dunno.

DoobyWho
08-11-2002, 11:03 AM
Consul - I saw that any network logo on your homepage, well, hmm, ive seen that logo on alot of web designer portfolios. No i can't name the urls, but i have seen it on others.

imago-allan
08-11-2002, 11:12 AM
Hi!

Which one do you mean? Please specify so we can take a look.
Thanks.

:)

Originally posted by DoobyWho
Consul - I saw that any network logo on your homepage, well, hmm, ive seen that logo on alot of web designer portfolios. No i can't name the urls, but i have seen it on others.

DoobyWho
08-11-2002, 11:13 AM
oops
any was supposed to be Ant

imago-allan
08-11-2002, 11:20 AM
EDIT:

Well, you might have seen it on our design reseller's or partner's webpages? I can assure you that the logo comes from us orginally. :)

It was requested by Dane Paz, the owner of First Ant Network through our free logo and banner design promo way back then here in WHT.

Thanks for pointing that out. If you can remember any URL feel free to give it to us so that we can verify if they are one of our design resellers or partners. Ok?

:)

DoobyWho
08-11-2002, 11:21 AM
I don't remember any, but feel free to show me a list of your design resellers (never heard of a design reseller.. heh.) or partners and ill see if that was were i saw it.

imago-allan
08-11-2002, 11:29 AM
Well, we do have design resellers or partners and they are supposed to be anonymous.

Basically, the portfolios to be displayed on their website will be the ones we design out of their orders. But, if they use the logos from our website, it is their prerogative. Yet, we still have to find out if they are really our partners. Otherwise, they are claiming something which is not theirs!

So if you happen to see it again, please do tell us. We don't give out our list of partners. Sorry.

:)

EDIT: By the way, the answer of Incognito is almost correct, but there is something to be done by the lawyer first so that the number of cars match exactly the fraction of the total cars.

DoobyWho
08-11-2002, 11:39 AM
I will let you know if I see it again.

Chicken
08-11-2002, 12:04 PM
Oddly, someone asked me this question just a week ago, though it was with cows, not cars. Answer is still the same :D

Confuses many people as they get thrown by 1/2 of 11 and feel that he should get 1/2 of the total and that the he's getting more than the others (6 does not equal 3+2, thus it isn't 1/2).

Annoying fraction problems eh? ;)

adammc
08-11-2002, 12:12 PM
I hate maths problems. Good job I'm not that lawyer.

DoobyWho
08-11-2002, 12:18 PM
Chicken - Yes, very annoying faction problems. :bawling:

imago-allan
08-11-2002, 12:49 PM
Hi all!

You know what the lawyer should do then? Here is my thought:

The lawyer should borrow another car to make the total to 12 cars.

Then, the following are the shares:

1/2 of 12 is 6 (that will make the eldest son happy since it is more than one-half of 11 which is 5 1/2).

1/4 of 12 is 3 (that is more than 2 3/4 which is 1/4 of 11. so the middle son is happy too.)

1/6 of 12 is 2 (definitely greater than 1 5/6 which is 1/6 of 11. so no complaint from the young one).

After they get all their share, they all have a total of 11 cars. The lawyer keeps the remaining car and return it from where he borrow!

Incognito does got it almost right. He just missed the point what the lawyer should do to make the division of the cars easy.

DoobyWho
08-11-2002, 12:51 PM
Doh.

AceWeb
08-11-2002, 02:45 PM
Good one :D

Lamont
08-12-2002, 12:29 AM
In the real world all your answers are wrong.

The real solution would be worked out like this:

The lawyer keeps all the cars and sends a bill to each of the brothers for his services.
The government taxes each of the brothers the full value of all 11 cars.

Website Rob
08-12-2002, 01:05 AM
As 6, 3, 2, is the correct divy of amounts, the only other thing I can see is the order of selection. The order would be one car at a time going from; youngest, middle, oldest, for 2 selections. Then middle picks another car and the remaining 4 go to the oldest.

Can't be much fairer than that!