Hi,
I have a script which begins with assigning values to $_POST and $_GET is they are not set:
if ( !isset($_POST['checkout_choice']) && !isset($_GET['choice']) )
{
$_POST['checkout_choice'] = 3;
$_GET['choice'] = 3;
}

It used to work fine on php4 shared server, but when I move to virtual server with php5 installed it wount work, its just not loading page like it will never execute.Can anyone please help me to solve this?

I don't think the problem lies on this code.

I think you are approaching it from the wrong direction - You are trying to set the $_GET and $_POST variables - Thats something which is supposed to be passed to the script. While it might of worked in v4, I wouldn't recommend doing it like that at all.

What about something like:
if ( !isset($_POST['checkout_choice']))
{
$checkout_choice = 3;
}
else
{
$checkout_choice = $_POST['checkout_choice'];
}

Surely it makes sense to assign to local variables huh? - Otherwise if you don't your going to go to what i call 'dependancy hell'. You cannot rely upon php not to change in each version - you can only rely upon yourself to save you from it!

oops. I messed up.

I'm wondering if it's throwing an error and you have display_errors off?

Usually PHP throws errors unless it actually crashes due to some weird code.

It dont shows any error, and display_errors is set to ON

take display_errors off, and check again

It dont shows any error, and display_errors is set to ON


To confirm this make an obvious syntax error. See if it produces any errors then.

I have tried to make syntax error, and I get error message for it.....

Did you read my post earlier?

there is nothing php4 or php5 specific in this your problem lies else where

Hi, guys. I have solved this problem by setting values separately like this
if ( !isset($_POST['checkout_choice']) ) $_POST['checkout_choice'] = 3;

if ( !isset($_GET['choice']) ) $_GET['choice'] = 3;
Apparentaly when one variable isn't set it is reseting other as well.Now I have another problem.One class function has to use one of these vars ($_GET[choice]) , so I do "global $_GET;" in that function but it seems that its not working , $_GET[choice] is empty.As I wrote before, this was working on php4.What might be a problem here?

global vars are bad, your code probably needs a re write, to make it php 5 nice, better putting your gets and posts into local vars and passing them via method arguments to your classes

Sounds like what i said too. Not that he took any notice "because it worked in php4"..

Luka, how many times must i repeat myself? - You can not rely on php to be the same in every version. You can only follow general good coding practice within the language to save you from dependancy problems.

I uderstand, I gues I will have to re-do this script from begining.

You don't need to re-do the script from the beginning. Just modify it to make use of local variables in a similar way to what I showed you above.

If you had read my first post properly in the first place i probably wouldn't be telling you again!

Note that most editors have a "Replace" option in their edit menu. You might find that useful ;)

Just as friendly note, PHP5 adds $_REQUEST instead of $_GET and $_POST. Makes life much easier :)

So I would assume that $_REQUEST grabs the variable no matter which method was used?

Sounds cool...

No assuming necessary; $_REQUEST is a documented predefined variable (http://www.php.net/manual/en/language.variables.predefined.php). The documentation says, in part:Variables provided to the script via the GET, POST, and COOKIE input mechanisms, and which therefore cannot be trusted.