this is what I got, but it still doesn't work for me :(

please help, and thanks in advance:


$type = ("new"|"hot"|"warm");

if($he != $type) {$cat = "hot.php"; } elseif {$he == "new") { $cat = "hot.php"; } elseif ($he == "hot") { $cat = "hot.php"; } elseif ($he = "warm") { $cat = "warm.php"; } else { $he = "hot.php" }

Helps to format the code to try and find where you went wrong (posting errors help as well). It looks like you had the following portion:

elseif {$he == "new")

If you look you'll see you have the curlybrace before $he instead of an open parentheses.

Try this:

$type = ("new"|"hot"|"warm");

if($he != $type) {
$cat = "hot.php";
} elseif ($he == "new") {
$cat = "hot.php";
} elseif ($he == "hot") {
$cat = "hot.php";
} elseif ($he = "warm") {
$cat = "warm.php";
} else {
$he = "hot.php"
}

You should be using switch case instead ifelseifs.


switch($he) {
case 'new':
$cat = "hot.php";
break;
case 'hot':
$cat = "hot.php";
break;
case 'warm':
$cat = "warm.php";
break;
default:
$cat = "hot.php";
}

oh boy ok... let me give this a shot

Warning: include($cat) [function.include]: failed to open stream: No such file or directory in

the reason I want those terms so that nobody can try to do sql injection... so it those terms are not use... I would like it to go to the default file which is hot.php

my apologies, switch worked great!!!

my apologies, switch worked great!!!

Including just a variable is a very dangerous practice, you should at least have something like this
<?
include ($var . ".php");
?>