Hi!

i am working to find and replace the text in the files that contains space in their file names.

my code is:


for F in `find /home/script/ -type f -name "*.xml" -print`;
do
mv "$F" "$F.tmp";
sed 's/lfs/ /g' "$F.tmp">$F;
rm "$F.tmp";
done

it works fine for the files without having space in their file name but doesn't work for files having space in it.

any suggestions?

Thanks

This seems bit easier

find /home/script/ -type f -name "*.xml" -exec replace "lfs" " " -- {} \;


If you do not have "replace" installed (script that gets installed as part of mysql package) you can make some kind of function that will do what you need


#!/bin/bash

function replacelfs(){
local myfile=$@
cat $myfile | sed 's/lfs/ /g' > $myfile
}

find /home/script/ -type f -name "*.xml" -exec replacelfs {} \;



Do test any of this on temporary data before you try using it. I just typed it here and it might misbehave.

Hi!

Thanks sasha, but it is not working. it gives me the following error

find: missing argument to '-exec'

i created the method replacelfs() but still it is not working

and i am using ingres database not mysql

Can anybody suggest something diferent rather than creating new package or function?

Thanks

Don't you need quotes around that last $F?

Hi!

Thanks sasha, but it is not working. it gives me the following error

find: missing argument to '-exec'


Sounds like you did not type in the complete find command line.
Please make sure that you typed ALL of it in.

Try it again.

Hi!

i tried again and again but still it is having same problem

gives me an error message

ta

Please paste in the exact command that you are using.

HI!

Thanks to all who replied to my query

i solved my problem by replacing the for loop with while loop in original code and now it is working perfectly

thanks