Hi guys,

I have this intranet where when I upload photos to my server, it automatically creates a html for me, and within that html, it gives me the direct link to the photo... however, I just want export/print/keep the values of it... Here is what I have so far:

$dp = "http://localhost/photo.php";
if (!$dp)
{
echo("<P>Error: unable to load URL file into $dp. Process aborted.</P>");
exit();
} else {
$sp = file_get_contents($dp);
// highlight_string($sp);

$search = ereg("http://users.jaz2.localhost/(.*).jpg", $sp, $content);
$surl = $content[1];
$file = (basename ($surl));

print $file;
}

I have about 20 links, and when I print, it ONLY print out one filename: mountain

Is there anyway I can make it print out more than just 1 basename?

Also, the JAZ2 is a folder name, and sometimes it changes, right now, it's only printing out whatever from JAZ2, is there anyway I can make it print out other folder as well, and put that folder in a value format like: $folderid?

Any kind of help would definately be helpful and appreciated.

I guess I'm asking the wrong question or something... Is what I'm asking eve possible?

How about, how do I loop that script above?

first of all, i really dont get the [color="red"] stuff you've added in that, and second, could you please explain again what you want to do, cause i really cant seem to understand it :S And a bit more of the code might be nice as well, where does $content come from?

You need to use preg_match_all() (http://php.net/preg_match_all) instead of ereg, then loop through the array of results.

First, thank you all that have been trying to help me.

the [color="red"] is something I add in so I can show it off or make a bold statement for easier reading of what I'm trying to say.

I basically have an html output files with a bunch of links directly to photos/image files that I need to extract... therefore, I want to write a script that find a common line and export it out to a $exportlink value for me.

You need to use preg_match_all() (http://php.net/preg_match_all) instead of ereg, then loop through the array of results.

I think this is perfect and is what I need to use. If I use ereg, it only gives me the last results on that page:

here is the actual html line that php can load up:

<a href="picture.php?lg=us&&player=1&pix_id=5825&album_id=301&file=http%3A%2F%2Fuser.st1.localhost%2F301%2F2-out-the-grass.jpg" onClick="count_file_download('154');" class="blue orange capitalize">view online<strong>1.96 MB</strong></a><span class="small">jpg</span>

I've been trying to do the preg_match_all and I'm getting no luck for it just to pull out and display: http%3A%2F%2Fuser.st1.localhost%2F301%2F2-out-the-grass.jpgas a value $example and so on, and I have about 12 of these links.

Please help and once again, thank you all for attempting to help.

This might work |(?:.*?)file=(.*?)(?:.*?)|mi

it doesn't work, just give me a blank page

How are you using it?

I'm using it:


preg_match_all ("|(?:.*?)file=(.*?)(?:.*?)|mi", $var, $matches);

I don't know how your code can work. The very first line should give a parse error:


$dp = "http://localhost/photo.php";


Change it to :


$dp = 'http://localhost/photo.php';

Oops, I didn't realize that you used the [color ="Red"] to highlight the code sections.

The following code should work:


<?php
$dp = "http://localhost/photo.php";

$sp = @file_get_contents($dp);
if ($sp === FALSE) {
echo("<P>Error: unable to read the URL $dp. Process aborted.</P>");
exit();
}

preg_match_all("(http://users.jaz2.localhost/(.*).jpg)", $sp, $content);

foreach($content[0] as $surl) {
echo basename($surl),'<br />';
}
?>

Perfect!!!! Thank you so much! It's quick, and simple... I've seen codes that could take up 2 pages to do what you just did. Once again, I want to thank all of those that has been helping me.

It's weird, I try to wget the results, which is fine, but the download takes a while and it seem like the php file restarted/reload itself... is there anyway we have it not do this?

What I do is that I wget for every result... is there anyway we can break/stop after the wget is done?

Your reload/restart is php timing out. This is a server setting, which you can override by set_time_limit() (http://php.net/set-time-limit).

max_execution_time 3000000 3000000
max_input_time 600000 600000
memory_limit 400M 400M

thats what my server specs is running at...

can anybody tell me why with those configurations still timesout page?

When i had timeout errors, i found that it was caused by the lack of output to the browser or shell which called the script... have it print a bit from time to time, and make sure you flush the cacher if you have something like ob running...

After many readings and googling, still can't find the right way to do this... how can I have it print a big from time to time when the command to grab happens already? please tell me what to do...

Oops, I didn't realize that you used the [color ="Red"] to highlight the code sections.

The following code should work:


<?php
$dp = "http://localhost/photo.php";

$sp = @file_get_contents($dp);
if ($sp === FALSE) {
echo("<P>Error: unable to read the URL $dp. Process aborted.</P>");
exit();
}

preg_match_all("(http://users.jaz2.localhost/(.*).jpg)", $sp, $content);

foreach($content[0] as $surl) {
echo basename($surl),'<br />';
}
?>


Is there anyway we can limit the results from showing all of it to say maybe 4?

A simple way would be to use the array_slice function.


<?php
$dp = "http://localhost/photo.php";

$sp = @file_get_contents($dp);
if ($sp === FALSE) {
echo("<P>Error: unable to read the URL $dp. Process aborted.</P>");
exit();
}

preg_match_all("(http://users.jaz2.localhost/(.*).jpg)", $sp, $content);

//Retrieve the first 4 elements only
$temp = array_slice($content[0], 0, 4);

foreach($temp as $surl) {
echo basename($surl),'<br />';
}
?>