Hi, I was wondering if those who know how to subnet, could look over this paper, tell me what they think, and if they find any errors. Only about a 5 min read or so. Thank you

http://64.246.33.110/subnet.txt

Hi.

Use the IP SubNet calculator from solarwinds.net
It is the best that i have found.

Thanks

This document is written for people going for the CCNA, you cant use a calculator on the test :(, so this is ment to help people learning it by hand.

Do you want a grammatical or technical critique, or both?

technical, grammer Ill do later, I know its bad, I was tired when I wrote this. But im concerned about technical
btw, I knew u would respond

How did you know I would respond :)?

Okay, one big mistake:


Now start at 32 and count out another 32 (remember, you are including 32 in the count) and as a result you get 32-64.


Should be 32-63

I am not sure how the CCNA interprets it, I posted on Chester's board to get a definitive answer, but technically, if your routing protocol supports classful routing, then you can get 8 /27 subnets out of a class C. The only routing protocol I know of -- that is used today -- which does not support classful routing is RIPv1. Anyone who is using RIPv1 on their network should be dragged out and shot.

I would also consider adding in an explaination of block notation in addition to the decimal notation. Since normal network admins speak block not decimal. ie:

192.168.100.64 255.255.255.224 = 192.168.100.64/27

I will change that.

I thought about doing it like that. But to be honest when I was first learning, and I saw it written like that, I was confused. I think I will add an explanation about it at the end.

btw, I was expecting a much longer errors, i hope you are stil not looking, heh

Sorry, still looking :D. Everything else looks pretty good...I have some minor quibbles. But they arise more out of my crochetiness than technical innacurracy.

If you want a CIDR chart you can steal, you are welcome to mine, though it is not anything spectacular:

http://www.allan.org/cidr.php

You are right. I might of got it from my 407 book, or mabey I just made it up. I just checked a new version of a book, and yes, its not 2^n-2 its just 2^n

Thanks for everything. I feel like a fool

Originally posted by davidb

Thanks for everything. I feel like a fool


No need. It wouldn't surprise me at all if the CCNA follows the 2^n-2 rule. Remember even the new versions ask about friggin ISDN ;-). That's why I am checking with Chester's baord to see if anyone knows for sure.

i was under the impression the CCNA did use the 2^n-2 rule. i could be wrong.

The Cisco Press 507 says 2^n for hosts

This is really confusing me now :(), as I think of it more, the practice tests I have taken, all use the -2

At any rate, I made the changes(hopefully got all of them) and did some work on the grammer. Please check it out, it is in word format this though. Also I have my Hex paper up there too, so if you would like, take a look.


BTW, in responce to a question up above from uuallan:
I just see you respond to a lot of networking question I have seen on the board, so I figured you knew and would respond to this :)

http://64.246.33.110/Subnetting.doc
http://64.246.33.110/Hex.doc

I really do hate doing subnets in my head :D
That something I'm going to regret on the CCNA exam... I can do everything else :D


Last I checked, the lastest CCNA curriculum for download doesn't even mention CIDR :D

Hmm.. That reminds me, I should prolly download it and start looking over it for next year.....:bawling:

I HATED it so much at first, I remember looking it over for the first few times, just horrible. At first I never got the concept of how the masks were generated and that there were only 8(for a class C). But once I got it, its not so bad doing it in my head. Its just a matter of putting some rules together and it goes fairly quick(of course I still use fingers).