What do you think about this...

If I've got 10 000 users per day on a site and if each user see 10 pages (50Ko each one), it means :

(10 000 x 10) x 50 = 5 000 000 Ko or 4,76MB per day and 143MB of data transfert (bandwidth) per month.

Is it correct please ? :)

Originally posted by Bot
(10 000 x 10) x 50 = 5 000 000 Ko or 4,76MB

Almost correct, you are only off by a factor of 1000 :)

1MB is roughly 1000KB (yea ... yea .. 1024KB :) )
So your 5 millions KB should be roughly equal to 5GB/day

so ... roughly 150GB/mo ...
See, you are only off by 'not much' :)

regards,
-dave

Lol, yep I make a little mistake with the french Ko and the english Kb :stickout

Thanx for your answer :)

yes that's about right 5 gigs per day.

but here is the best question

when does the usage hit peak, if the page loads are happening all at one time, 1 mbit = about 10.2 gigs a day or about 500 megs an hour.


then you as a customer of a web shop need to have access to a 3 mbit pipe. this is based that 30% of the activity will happen over a 2 hour basis. and the rest is normal.

Just something to consider.

SIde note: anybody think differently please post, I ran into this problem 2 months ago and came up with the above solution after looking at the consumtion graph.

Mike

Don't forget to lower the number for cached pages. Looking at my own server logs for a high volume site I run, I'm surprised at how many pages are actually cached and not really transferred.

Originally posted by hostpath.com
Don't forget to lower the number for cached pages. Looking at my own server logs for a high volume site I run, I'm surprised at how many pages are actually cached and not really transferred.

good point, I did not even think of that,

mike

That's right, it's important.