Ok, why does:

cat /usr/local/apache/conf/httpd.conf | grep $ARG1 -B 13 -A 10 > /tmp/httpd.conf

Return the 27 lines of httpd.conf that i want to delete, but:

cat /usr/local/apache/conf/httpd.conf | grep -v $ARG1 -B 13 -A 10 > /tmp/httpd.conf

Return the whole httpd.conf, line by line and does not remove the 27 lines?

Thanks,

-v Displays all lines not matching the specified pattern.
Maybe that's why?

I am trying to remove the 27 lines and save the rest to a file.

Thanks,

why would you ever do this:

cat file | grep

Its silly..

how about:

grep -options file

hmm, it is a 2.5 MB httpd.conf file and i need to remove 800+ vitural hosts via a username list.

I tried grep -options file and it hung.

This is what I am trying:


#!/bin/sh -x
for ARG1 in `cat /tmp/users.txt`; do
#echo $ARG1
cat /usr/local/apache/conf/httpd.conf | grep -v $ARG1 -B 13 -A 10 > /tmp/httpd.conf
exit
#cp /tmp/httpd.conf /usr/local/apache/conf/httpd.conf
done