Hey Guys,

I need a simple way to verify that someone is 13 years old. It needs to be done through PHP and the age format was made by date() and looks like this:

"March 5, 1990"

Anyone know how to do this?

Much thanks for your help in advance!

-Chris

You probably want to use mktime to get the timestamp for 13 years ago. Then use strtotime to break the date you have into a timestamp. Then compare. There are several examples in the user comments in the PHP manual.

<?php

$date = "March 5, 1990";

function check_age($age){
return (strtotime('13 years ago') > strtotime($age));
}

$results = (check_age($date))? 'Yes':'No';

echo "Birthdate: $date\n";
echo "Are you 13? $results\n";
?>

Works Perfectly! Thank you very much malenski!

-Chris

The easier way!!

<?php

$age = date("Y") - $_POST['year'];
if ($age < 13) {
die("WRONG AGE DUMMIE");
}

?>

It's also the wrong way -- depending on when they were born within the year, they could only be 12 (and some change) and still pass.

strtotime() is a really fun function.

Using die() also isn't a very good way of posting messages. There may be more code that needs to run, such as including a footer or something. Malenski's code is the best way to go about it.

strtotime() is a cool function but it worries me to rely on a function that will supposedly decode english into a number. For this i'd likely just use 409968000 as the number of seconds in 13 years. This is just a personal preference though.

The number of seconds in 13 years changes depending on the years.

I agree you should validate the format of the string you send to strtotime before using it.

very true.

Yeah I do agree using die() isnt a good idea.

Lol I dont use die ;) I just used it in the example.

I have error() and notice() functions :D:D