Hello

I need to use PHP to pass parameter values
to shell
but I don't know how to do it!!

pls help!

thanks a lot

Look at these functions
http://php.net/exec
http://php.net/system

if you do a

./php testvar.php -f=plah -g=pleh ,xyz=fnuk

to start your php from shell

then try "testvar.php" with the following code

#!/usr/bin/php
<?
var_dump($argv);
?>

i guess its what youre looking for

Umm I try to make usershow.sh to recieve from viewuser.php
in php file I can use exec() to run usershow.sh
but I want to pass parameter such as $username
to shell script but I don't know how to write shell to recieve and how php pass value to shell by use exec() or system()

Thanks for every one :D

I hope this gives you an idea, if i understood you correctly try this:
PHP part:

<?php
system('/path/to/test.sh variable1');
?>

Shell (bash) part:

#!/bin/bash
echo $1


Chmod the .sh with something like 755 and then run your php script

if you want to pass params during the runtime, you need to use any stream for.

i.e.

you can read a textfile for new lines
also you could stress mysql (selecting a table)
or you implement a socketlistener (AF_UNIX) to your script

else threre is no chance to passing vars during the scriptruntime. Not that i know.

It still not work for use php to pass value to shell
I'm ok to write shell to recieve parameter form console
but pass with PHP is still not work
example

I write
on PHP
<?
shell_exec(" ./mkdir.sh newdir ");
?>

on shell
#!/bin/bash
mkdir $1

and chmod 755 with shell
I can run shell by command line ./mkdir.sh new_dir

It's OK

What should I do in this way or I have another problem with server sevice because my RH9 server is not compleately runing well

Thanks a lot for every one