there is a file like http://localhost/test.html which contents more than ten dl url in that file like http://1234.com/test1.zip , http://2345.com/test2.zip , and http://4532.com/test3.zip etc....

What is the best way to get all the files in test.html ? Thanks

From the wget manual :


-i file
--input-file=file
Read URLs from file, in which case no URLs need to be on the command line. If there are URLs both on the command line and in an
input file, those on the command lines will be the first ones to be retrieved. The file need not be an HTML document (but no harm
if it is)---it is enough if the URLs are just listed sequentially.

However, if you specify --force-html, the document will be regarded as html. In that case you may have problems with relative
links, which you can solve either by adding "<base href="url">" to the documents or by specifying --base=url on the command line.

Thanks for your help, but I still don't get it. ;(

Can you show me more specific detail ?

Like there 2 links like http://1234.com/asdf.zip and http://1234.com/jkl.zip in http://localhost.com/test.html

Then how do I use the command --input-file like you just showed me? Thanks

wget -i --force-html http://localhost.com/test.html

should work

It doesn't work for me. It just dl the .html file not the file in .html . It showed up on the screen is

--force-html: No such file or directory
No URLs found in --force-html.

Are these files links on that html page?

If they are, and in a lower or the same directory try this

wget -r -np http://wwww.test.com/test1.html

Take a look at the manual page. ;)

perhaps there are some security or privilege issues you are unaware of? Airnine

If you want to just mirror a directory you can do wget -mp http://....